[kkasp]

Hi, I am trying to convert a color image (smokey.gif) to grayscale and then to sepia.
The function is called sepia and it is supposed to call grayscale first.
Here is what I have so far, any suggestions?

import Image

def sepia (image, grayscale):
    if red < 63:
        red = int(red * 1.1)
        blue = int(blue * 0.9)  
    elif red < 192:
        red = int(red * 1.15)
        blue = int(blue * 0.85)
    else:
        red = min(int(red * 1.08), 255)
        blue = int(blue * 0.93)
        
def grayscale(image):
    for y in xrange(image.getHeight()):
        for x in xrange(image.getWidth()):
            (r, g, B)/> = image.getPixel(x, y)
            r = int(r * 0.299)
            g = int(g * 0.587)
            b = int(b * 0.114)
            lum = r + g + b
            image.setPixel(x, y, (lum, lum, lum))
    
def main(filename = "smokey.gif"):
    image = Image(smokey.gif)
    print "Close the image window to continue."
    image.draw()
    sepia(image)
    print "Close the image window to quit."
    image.draw()
main()

The error I am getting is
Traceback (most recent call last):
File "C:\Python27\7_8", line 40, in <module>
main()
File "C:\Python27\7_8", line 34, in main
image = Image(smokey.gif)
NameError: global name 'smokey' is not defined

which I am not sure why- I have the file smokey saved in my working directory.
Thanks in advance for any help.
Kkasp

[Motoma]

On line 25, image = Image(smokey.gif).

You will need to encapsulate the file name in either quotes or apostrophes. More likely, you'll want to use the filename variable instead.

[kkasp]

thanks, that was a stupid mistake.... I am going to send to my prof and get his input also.