1 Replies - 628 Views - Last Post: 29 October 2011 - 12:05 PM

#1 saxasm   User is offline

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AJAX loading of next question in form not working

Posted 28 October 2011 - 08:34 AM

So, my javascript:
<script type="text/javascript">
function stopselect(county)
   request = new XMLHttpRequest();

I have checked, and the event catch most definitely works and this function is called.

warnajax.php is extremely simple:
echo $_GET['county'];

The code that prints the form in question looks like:
$query = "SELECT DISTINCT county FROM rawxmldata ORDER BY county;";
$result = mysql_query($query) or die(mysql_error());
echo '<form method="post" action="createwarn.php">Välj kommun: <select onchange="stopselect(this.options[this.selectedIndex].value)" name="county">';
while($row = mysql_fetch_array($result, MYSQL_ASSOC))
   $county = preg_split("/ /",$row['county']);
   $countyname = $county[0].$county[1];
   echo '<option value="'.$countyname.'">'.$row['county']."</option>
echo "</select>";
echo '<div id="stopselection"></div>';
echo "</form>";

I'm an extreme noob at all AJAX and javascript things, so the only thing I've tried so far is removing all superfluous code. It should load another <select> letting the user select what bus stop in the county to choose, once it is done. Anyone able to see why it fails?

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Replies To: AJAX loading of next question in form not working

#2 VolcomMky   User is offline

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Re: AJAX loading of next question in form not working

Posted 29 October 2011 - 12:05 PM

Is it hitting the ajax page with the full url?

"The concat() method is used to join two or more arrays.

This method does not change the existing arrays, it only returns a copy of the joined arrays."
- W3Schools

I would replace this
with this

This post has been edited by VolcomMky: 29 October 2011 - 12:05 PM

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