[nitin25]

int &add(int &ref)
{
 
ref+=1;
return ref;
}

int main()
{

int b=5;
int &mref=b;
add(mref);	//POINT OF DOUBT
return 0;
}

FUNCTION ADD IS RETURNING A REFERENCE BUT WHEN USED IN MAIN ITS RETURN TYPE IS NOT ASSIGNED TO ANYTHING. SO WHAT WILL HAPPEN TO REFERENCE RETURNED BY ADD IN MAIN.

[1lacca]

It doesn't matter since the program ends there anyway

Just print it out on the next line, and you'll see.



spoiler: both mref, and b will be 6.
the reference returned by add is "lost", because you dont assign it to anything, however the things done in the function are not lost, because they are done on a reference.

[Xing]

nitin25, on 16 Aug, 2007 - 02:51 AM, said:

FUNCTION ADD IS RETURNING A REFERENCE BUT WHEN USED IN MAIN ITS RETURN TYPE IS NOT ASSIGNED TO ANYTHING. SO WHAT WILL HAPPEN TO REFERENCE RETURNED BY ADD IN MAIN.

You can ignore return values in C and C++.

PS: Do not use all caps. It is termed as shouting in this part of world.

[vijaysnkar]

Yes, The return values are ignored in this case because the program will end up.

Xing, on 15 Aug, 2007 - 10:04 PM, said:

nitin25, on 16 Aug, 2007 - 02:51 AM, said:

FUNCTION ADD IS RETURNING A REFERENCE BUT WHEN USED IN MAIN ITS RETURN TYPE IS NOT ASSIGNED TO ANYTHING. SO WHAT WILL HAPPEN TO REFERENCE RETURNED BY ADD IN MAIN.

You can ignore return values in C and C++.

PS: Do not use all caps. It is termed as shouting in this part of world.

[Xing]

vijaysnkar, on 16 Aug, 2007 - 12:29 PM, said:

Yes, The return values are ignored in this case because the program will end up.

What do you mean program ends up?
Ignoring of return values has nothing to do with ending of program.

[vijaysnkar]

OK

Xing, on 16 Aug, 2007 - 02:29 AM, said:

vijaysnkar, on 16 Aug, 2007 - 12:29 PM, said:

Yes, The return values are ignored in this case because the program will end up.

What do you mean program ends up?
Ignoring of return values has nothing to do with ending of program.

[nitin25]

Thank's to all for explaining the above code.