# Add & Reduce 2 fractions

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## 2 Replies - 2536 Views - Last Post: 13 December 2012 - 09:53 PM

### #1 DeeViLiSh

Reputation: 6
• Posts: 175
• Joined: 25-July 06

# Add & Reduce 2 fractions

Posted 28 August 2006 - 10:41 PM

Description: Use this like you want, no credits neededInput two fractions, program outputs them added and reduced
```#include<iostream.h>

//Inputs the fractions
void ReadFraction(int &Num, int &Denom, int &Num2, int &Denom2)

{
cout << "Enter the numerator for the first fraction: ";
cin >> Num;
cout << "Enter the denominator for the first fraction: ";
cin >> Denom;
cout << endl;
cout << "Enter the numerator for the second fraction: ";
cin >> Num2;
cout << "Enter the denominator for the second fraction: ";
cin >> Denom2;
cout << endl;

}

void Reduce(int &Num, int &Denom, int &Num2, int &Denom2)

{
int a, b, c, d, i, j = 0;

a = Denom;
b = Num;
c = Denom2;
d = Num2;

for (i = a * b; i > 1; i--)
{
if ((a % i == 0) && (b % i == 0))
{
a /= i;
b /= i;
}
}

for (j = 50; j > 1; j--)
{
if ((c % j == 0) && (d % j == 0))
{
c /= j;
d /= j;
}
}

Denom = a;
Num = b;
Denom2 = c;
Num2 = d;

}

void Reduce(int &Num, int &Denom)
{
int a = 0;
int b = 0;
int i = 0;

a = Denom;
b = Num;

for (i = 50; i > 1; i--)
{
if ((a % i == 0) && (b % i == 0))
{
a /= i;
b /= i;
}
}

Denom = a;
Num = b;
}

void AddFraction(int &Num, int &Denom, int &Num2, int &Denom2)
{
if (Denom != Denom2)
{

Num = Num * Denom2;
Num2 = Num2 * Denom;
Denom = Denom * Denom2;
Denom2 = Denom2 * Denom;
Num = Num + Num2;
}
else
{
Num = Num + Num2;
}

Reduce(Num, Denom);
}

void DisplayFraction(int &Num, int &Denom)
{
cout << "The reduced and added fraction is " << Num << "/" << Denom << endl;
}

int main()
{
char an;

do
{
int Num, Denom, Num2, Denom2 = 0;

Reduce(Num, Denom, Num2, Denom2);
DisplayFraction(Num, Denom);
cout << endl;

cout <<"Would you like to do another fraction? (Y for yes) ";
cin >> an;
cout << endl;
}while ((an == 'y') || (an == 'Y')); //Continues or not

return 0;
}
```

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## Replies To: Add & Reduce 2 fractions

### #2 chandravir

Reputation: 0
• Posts: 0
• Joined: 16-December 08

## Re: Add & Reduce 2 fractions

Posted 16 December 2008 - 07:23 AM

it's verygood

### #3 antolyevich

Reputation: -6
• Posts: 12
• Joined: 02-September 12

## Re: Add & Reduce 2 fractions

Posted 13 December 2012 - 09:53 PM

Using a counter i for reduction is a really inefficient way to work with larger fraction, maybe array sort the factors and binary search for common factors, bubble sort and take the lowest