[PlzHalpCode]

Write a function number_of_pennies() that returns the total number of pennies given a number of dollars and (optionally) a number of pennies. Ex: 5 dollars and 6 pennies returns 506.

def number_of_pennies(dollars, pennies):
   if pennies == 0:
      dollars = dollars * 100
      return(dollars)
            
   if pennies>0:
      dollars = dollars * 100
    
   return(dollars+pennies)
      
print(number_of_pennies(5, 6)) # Should print 506
print(number_of_pennies(4))    # Should print 400

I can't make the last print statement ignore the pennies argument!

here's the error

506
Traceback (most recent call last):
  File "main.py", line 12, in 
    print(number_of_pennies(4))    # Should print 400
TypeError: number_of_pennies() missing 1 required positional argument: 'pennies'

[andrewsw]

You included the term "optional argument" in your title, did you try searching this term?

Using Optional and Named Arguments

def number_of_pennies(dollars, pennies=0):

This post has been edited by andrewsw: 01 February 2015 - 02:24 AM

[CreamDelight]

In addition to the answer above, you may also try to use ternary operator (or so called ternary operator, read it here: https://www.python.o.../peps/pep-0308/) to reduce your code to make it look more like a python.

def number_of_pennies(dollars, pennies=0):
    return dollars * 100 if pennies == 0 else dollars * 100 + pennies