[key01023]

hi i have a unknown string in c++ containing "\n" "\t" etc.
say;
string unknown1="\n\t\n\t\n\n\n\n\n";
now I want to print

"\n\t\n\t\n\n\n\n\n"

to the screen explcitly other than a bunch of empty spaces.... how should I do that? remember that I don't know what is in unknown1...

[infernorthor]

you need to escape the \ , the extra \ creates an '\' leaving the n normal

"\\n" would print "\n"

This post has been edited by infernorthor: 28 April 2015 - 08:02 PM

[key01023]

infernorthor, on 28 April 2015 - 08:01 PM, said:

you need to escape the \ , the extra \ creates and \ leaving the n normal

"\\n"

That is just an example.... I don't know what is inside unknown_string...... I just want to visualize the string explicitly....

[infernorthor]

I get you now. You need create a for loop to print it out the way you want. check for those characters like

char c;
if( c == '\n' )
    cout << "\\n"; 

[key01023]

infernorthor, on 28 April 2015 - 08:05 PM, said:

I get you now. You need create a for loop to print it out the way you want. check for those characters like

char c;
if( c == '\n' )
    cout << "\\n"; 

but actually, when I started to learn c++. I remember there is a way to print strings explicitly... using some functions.... sometimes the string might contain something that I don't even know their existence, so I could not check every single characters.... for example there might be some char corresponding to \u that i don't know of.... Thank you:D

[infernorthor]

for those cases the only option is to print the number
cout << (int) c;

if you want the hex
#include <iomanip> and do
std::cout << std::hex << (int) c;

[#define]

The header <cctype> (ctype.h) has character classification routines.