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#1 Prochotap   User is offline

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How to Sumarize leave time proportionally and correctly - mysql

Posted 04 April 2019 - 08:57 AM

Hello all programmers! :)

In mysql database i created "leave" table:

CREATE TABLE `leave` ( 
`ID_LEAVE` int(11) NOT NULL,
`ID_WORKER` int(11) NOT NULL,
`BEGIN_DATE` datetime DEFAULT NULL,
`END_DATE` datetime DEFAULT NULL
)

INSERT INTO `leave` 
(`ID_LEAVE`, `ID_WORKER`, `BEGIN_DATE`, `END_DATE`) VALUES
(3, 26, '2019-03-20 07:00:00', '2019-03-21 15:00:00'),
(4, 22, '2019-03-20 07:00:00', '2019-03-20 15:00:00');
"Workers" table:

CREATE TABLE `workers` (
`ID_WORKER` int(11) NOT NULL,
`FNAME` varchar(20) NOT NULL,
`LNAME` varchar(20) NOT NULL
)

INSERT INTO `workers` (`ID_WORKER`, `FNAME`, `LNAME`) VALUES
(22, 'ALAN', 'FAST'),
(23, 'LEON', 'SPEED'),
(24, 'ADAM', 'GREEN'),
(25, 'DAVID', 'BUCS'),
(26, 'JACK', 'FAR'),
(27, 'ADAM', 'GAX'),
(28, 'ANDREW', 'WORM');


"Orders" table:

CREATE TABLE `orders` (
`ID_ORDER` int(11) NOT NULL,
`DESC_ORDER` varchar(50) NOT NULL,
`NUMBER_ORDER` varchar(30) NOT NULL
)

INSERT INTO `orders` (`ID_ORDER`, `DESC_ORDER`, `NUMBER_ORDER`) VALUES
(19, 'TEST', 'TEST'),
(20, 'TEST2', 'TEST2'),
(21, 'TEST3', 'TEST3'),
(22, 'TEST4', 'TEST4');


"Order_status" table (I'm sorry for that's not in order):
CREATE TABLE `order_status` (
`ID_STATUS` int(11) NOT NULL,
`ID_ORDER` int(11) NOT NULL,
`ID_WORKER` int(11) NOT NULL,
`BEGIN_DATE` datetime NOT NULL,
`END_DATE` datetime NOT NULL,
`ORDER_DONE` tinyint(1) DEFAULT NULL
) 

INSERT INTO `order_status` (`ID_STATUS`, `ID_ORDER`, `ID_WORKER`, `BEGIN_DATE`, `END_DATE`, `ORDER_DONE`) VALUES
(30, 19, 26, '2019-03-18 06:40:21', '2019-03-18 15:22:32', 0),
(31, 19, 25, '2019-03-18 06:51:23', '2019-03-18 15:11:10', 0),
(32, 19, 26, '2019-03-20 06:23:32', '2019-03-20 15:33:11', 0),
(33, 19, 25, '2019-03-20 06:44:42', '2019-03-20 15:16:22', 0),
(34, 19, 26, '2019-03-22 06:44:32', '2019-03-22 11:44:54', 1),
(35, 19, 25, '2019-03-22 06:59:22', '2019-03-22 12:33:33', 1),
(42, 20, 22, '2019-03-18 06:44:23', '2019-03-18 15:11:23', 0),
(43, 20, 23, '2019-03-18 06:50:45', '2019-03-18 15:15:44', 0),
(44, 20, 22, '2019-03-19 06:40:20', '2019-03-19 15:23:30', 0),
(45, 20, 22, '2019-03-21 06:55:45', '2019-03-21 16:03:23', 0),
(46, 20, 22, '2019-03-22 06:55:45', '2019-03-22 13:23:44', 1),
(47, 20, 23, '2019-03-19 06:45:23', '2019-03-19 15:33:23', 0),
(48, 20, 23, '2019-03-20 06:45:23', '2019-03-20 15:22:23', 0),
(49, 20, 23, '2019-03-21 06:50:33', '2019-03-21 15:33:11', 0),
(50, 20, 23, '2019-03-22 06:44:23', '2019-03-22 12:22:44', 1),
(51, 21, 24, '2019-03-18 06:46:55', '2019-03-18 15:23:22', 0),
(52, 21, 24, '2019-03-19 06:55:33', '2019-03-19 15:23:33', 0),
(53, 21, 24, '2019-03-20 06:50:59', '2019-03-20 15:44:02', 0),
(54, 21, 24, '2019-03-21 06:44:33', '2019-03-21 15:23:33', 1),
(55, 21, 24, '2019-03-22 06:49:33', '2019-03-22 11:22:32', 1),
(56, 22, 27, '2019-03-18 06:50:12', '2019-03-18 15:22:15', 0),
(57, 22, 28, '2019-03-18 06:44:12', '2019-03-18 15:33:44', 0),
(58, 22, 27, '2019-03-19 06:53:22', '2019-03-19 15:22:33', 0),
(59, 22, 28, '2019-03-19 06:33:22', '2019-03-19 15:15:22', 0),
(60, 22, 28, '2019-03-21 06:33:22', '2019-03-21 15:01:56', 0),
(61, 22, 27, '2019-03-22 06:33:22', '2019-03-22 11:05:33', 1),
(62, 22, 27, '2019-03-21 06:45:22', '2019-03-21 15:33:33', 0),
(63, 22, 28, '2019-03-22 06:51:33', '2019-03-22 10:35:55', 1),
(64, 19, 25, '2019-03-19 06:50:32', '2019-03-19 15:33:44', 0),
(65, 19, 26, '2019-03-19 06:44:50', '2019-03-19 15:22:33', 0),
(66, 19, 25, '2019-03-21 06:50:50', '2019-03-21 15:33:33', 0);
(67, 22, 27, '2019-03-20 06:51:32', '2019-03-20 15:20:33', 0);


What i've done:

I can to sumarize "Order time" of each other workers. I have selected workers (LNAME, FNAME) orders (DESC_ORDER and NUMBER_ORDER) and "TOTAL TIME" on order from each other workers correctly too. I wrote the mysql command in below:

SELECT workers.FNAME,
workers.LNAME,
order_statusAgg.NUMBER_ORDER,
order_statusAgg.DESC_ORDER,
SEC_TO_TIME(SUM(order_statusAgg.stime)) AS 'ORDER TIME'
FROM workers
LEFT JOIN (
SELECT order_status.ID_WORKER, orders.NUMBER_ORDER, orders.DESC_ORDER,
SUM((TIME_TO_SEC(order_status.END_DATE) - TIME_TO_SEC(order_status.BEGIN_DATE))) AS stime
FROM order_status INNER JOIN orders
ON orders.ID_ORDER = order_status.ID_ORDER
GROUP BY order_status.ID_WORKER) order_statusAgg
ON workers.ID_WORKER = order_statusAgg.ID_WORKER
WHERE order_statusAgg.NUMBER_ORDER LIKE 'TEST'
GROUP BY workers.ID_WORKER;

+---------+---------+---------------+------------+------------+
|  FNAME  | LNAME   |  NUMBER_ORDER | DESC_ORDER | ORDER TIME |
+---------+---------+---------------+------------+------------+
|  DAVID  |  BUCS   | TEST          | TEST       | 39:51:33   | 
+---------+---------+---------------+------------+------------+
|  JACK   |  FAR    | TEST          | TEST       | 31:29:55   |
+---------+---------+---------------+------------+------------+


I've analyzed 2 days (20.03.2019 and 21.03.2019). Photos are in below:

Posted Image

Posted Image

Now i need mysql query that sumarize leave time correctly and PROPORTIONALLY to pattern described in below:

Posted Image

for example for leave time where ID_WORKER = 26 (he has order "TEST")

                    '08:31:40'                                      '08:31:40'
(-------------------------------------------------) * 8:00:00 =  (--------------) * 8:00:00 = 2:00:16
 '08:31:40' + '08:37:00' + '08:53:03' + '08:29:01'                  '34:30:44'


What I've tried: I've tried sum leave time by mysql query in below:

SELECT workers.FNAME, 
workers.LNAME, 
order_statusAgg.NUMBER_ORDER,
order_statusAgg.DESC_ORDER, 
SEC_TO_TIME(SUM(order_statusAgg.stime)) AS 'ORDER TIME', 
IFNULL(SEC_TO_TIME(SUM(leaveAgg.ltime)),'00:00:00') AS 'LEAVE TIME'
FROM workers
LEFT JOIN (SELECT leave.ID_WORKER, SUM((datediff(leave.BEGIN_DATE, leave.END_DATE) + 1) * (time_to_sec(time(leave.END_DATE)) - time_to_sec(time(leave.BEGIN_DATE)))) AS ltime FROM leave
LEFT JOIN
(SELECT ID_WORKER, MIN(BEGIN_DATE) AS 'MIN_BEGIN_DATE', MAX(END_DATE) AS 'MAX_END_DATE' 
FROM order_status GROUP BY ID_WORKER) ordstat ON 
leave.ID_WORKER = ordstat.ID_WORKER 
WHERE leave.END_DATE <= MAX_END_DATE AND leave.BEGIN_DATE >= MIN_BEGIN_DATE GROUP BY leave.ID_WORKER) leaveAgg
ON leaveAgg.ID_WORKER = workers.ID_WORKER
LEFT JOIN (
SELECT order_status.ID_WORKER, orders.NUMBER_ORDER, orders.DESC_ORDER, 
SUM((TIME_TO_SEC(order_status.END_DATE) - TIME_TO_SEC(order_status.BEGIN_DATE))) AS stime 
FROM order_status INNER JOIN orders
ON orders.ID_ORDER = order_status.ID_ORDER
GROUP BY order_status.ID_WORKER) order_statusAgg
ON workers.ID_WORKER = order_statusAgg.ID_WORKER
WHERE order_statusAgg.NUMBER_ORDER LIKE 'TEST'
GROUP BY workers.ID_WORKER;


But I'm afraid that isn't enough because it only adds for example:

31:29:55 + 8:00:00 = 39:29:55


I wanna get that result:
31:29:55 + 2:00:16 = 34:00:11


CAUTION! If someone get's 2 or more days of leaves i cannot do that like this:

                    '08:31:40'                                      
(-------------------------------------------------) * 16:00:00 
 '08:31:40' + '08:37:00' + '08:53:03' + '08:29:01' 


I have to analyze every day like that example where i explained.

I know that's more difficult question i cannot find any clue how to solve it. Can someone please what should i change or add. I'm not SQL guru. I'm learning SQL for 4 weeks. Thank you in advance for any help or advice.

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Replies To: How to Sumarize leave time proportionally and correctly - mysql

#2 modi123_1   User is online

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Re: How to Sumarize leave time proportionally and correctly - mysql

Posted 04 April 2019 - 09:02 AM

I am not understanding what you are looking for with "Order time" and "TOTAL TIME". Run that by me again.
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