# Sequence making code Python 3.0

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### #1 Yerlan999

Reputation: 0
• Posts: 1
• Joined: 06-July 19

# Sequence making code Python 3.0

Posted 06 July 2019 - 05:01 AM

This piece of code tries to find a sequnce of number {which only somprises of this numbers (1, 2, 3, 4, 5, 6, 7, 8, 9)} that would satisfy the following reqirements. The very first two numbers have to be divisable to 2, and the first three divisable to three and so on.
Every time I run this code it takes several attempts and gives back an error.

Traceback (most recent call last):
File "..\Playground\", line 19, in <module>
main_list.remove( b );
ValueError: list.remove(x): x not in list

I am attaching the code (theCode.py), so you can run and test it if you want.
Maybe this task has no any solution at all. I am not sure. What am I doing wrong?

I need some advice in figuring out what is wrong with this code/ Thanks a lot in advance!

```import random

x = 0;

while x == 0 :

main_list = [1, 2, 3, 4, 6, 7, 8, 9]
e = 5;

a = random.choice(main_list);
b = random.choice(main_list);

main_list.remove(a);
main_list.remove( b );

n_1 = str(a) + str( b )

print(n_1)
print(main_list)

if (int(n_1) % 2) == 0:
#continuation of the code execution
print ("Everything is Okay ;-)  GOING ON...")

c = random.choice(main_list);

main_list.remove(c);

n_2 = str(n_1) + str(c);

print(n_2)
print(main_list)

if (int(n_2) % 3) == 0:
#continuation of the code
print ("Everything is Okay ;-)  GOING ON...")

d = random.choice(main_list);

main_list.remove(d);

n_3 = str(n_2) + str(d);

print(n_3)
print(main_list)

if (int(n_3) % 4) == 0:
#continuation of the code
print ("Everything is Okay ;-)  GOING ON...")

n_4 = str(n_3) + str(e);

print(n_4)
print(main_list)

if (int(n_4) % 5) == 0:
#continuation of the code
print ("Everything is Okay ;-)  GOING ON...")

f = random.choice(main_list);

main_list.remove(f);

n_5 = str(n_4) + str(f);

print(n_5)
print(main_list)

if (int(n_5) % 6) == 0:
#continuation of the code
print ("Everything is Okay ;-)  GOING ON...")

g = random.choice(main_list);

main_list.remove(g);

n_6 = str(n_5) + str(g);

print(n_6)
print(main_list)

if (int(n_6) % 7) == 0:
#continuation of the code
print ("Everything is Okay ;-)  GOING ON...")

h = random.choice(main_list);

main_list.remove(h);

n_7 = str(n_6) + str(h);

print(n_7)
print(main_list)

if (int(n_7) % 8) == 0:
#continuation of the code
print ("Everything is Okay ;-)  GOING ON...")

i = random.choice(main_list);

main_list.remove(i);

n_8 = str(n_7) + str(i);

print(n_8)
print(main_list)

if (int(n_8) % 9) == 0:
#finalizing part of the code
print (n_8)
print ("Everything is DONE ;-) ")
print ("The Code execution has FINISHED!!!")

x = 1;
break

else:
print ("Ooops, something went wrong....start it again, please! ")
continue
else:
print ("Ooops, something went wrong....start it again, please! ")
continue
else:
print ("Ooops, something went wrong....start it again, please! ")
continue
else:
print ("Ooops, something went wrong....start it again, please! ")
continue
else:
print ("Ooops, something went wrong....start it again, please! ")
continue
else:
print ("Ooops, something went wrong....start it again, please! ")
continue
else:
print ("Ooops, something went wrong....start it again, please! ")
continue
else:
print("Ooops, something went wrong....start it again, please! ")
continue

```
/>/>/>

#### Attached File(s)

This post has been edited by modi123_1: 06 July 2019 - 05:11 AM

Is This A Good Question/Topic? 0

## Replies To: Sequence making code Python 3.0

### #2 modi123_1

• Suitor #2

Reputation: 15262
• Posts: 61,171
• Joined: 12-June 08

## Re: Sequence making code Python 3.0

Posted 06 July 2019 - 05:18 AM

```011	    a = random.choice(main_list);
012	    b = random.choice(main_list);
013
014	    main_list.remove(a);
015	    main_list.remove( b );
```

What happens if a and b are the same number? You would remove it once in line 14, and then attempt to remove it again in line 15.