[colinwsun]

here is my code:

import javax.swing.*;
public class sun_wenqian_A2Q1 {
  public static void main(String args[]){
	
	//declare variables within main
	String strInput;
	String digits;
	
	
	//asking user to enter input
	strInput = JOptionPane.showInputDialog("Please enter a phone number or press q to quit the program!");

	while(strInput.equals("q")){
	  digits = strInput.Replace("(","").Replace(")","").Replace("-","");
	  
	  int i = 0; // declare i for loops 
	  
	  while(Character.isDigit(digits.charAt(i))){
		i++;
		numDigits = Integer.parseInt(digits);
		
		//4 kind of Phone numbers:nnnnnn,nnnnnnnnnn,nnnnnnnnnnn,if it's not "204",it's long distance
		if(numberDigits = 7){
		  Systerm.out.println("User entered: "+strInput);
		  Systerm.out.println("Phone number parsed: ");
		  Systerm.out.println("Valide phone number: ");
		}else if(numberDigits = 10){
		  Systerm.out.println("User entered: "+strInput);
		  Systerm.out.println("Phone number parsed: ");
		  Systerm.out.println("Area code: ");
		  Systerm.out.println("Valide phone number: ");
		}else if(numberDigits = 11){
		  Systerm.out.println("User entered: "+strInput);
		  Systerm.out.println("Phone number parsed: ");
		  Systerm.out.println("Area code: ");
		  Systerm.out.println("Valide phone number: ");
		}else{
		  Systerm.out.println("User entered: "+strInput);
		  Systerm.out.println("No Phone number parsed, invalid!");
		}//end of if else if 
		
		  
		
	  }//end of while loops of "isDigits"
	  Systerm.out.println("User entered: "+strInput);
	  Systerm.out.println("No Phone number parsed, invalid!");
	  
	  
	  
	  //strInput = JOptionPane.showInputDialog("Please enter a phone number or press q to quit the program!");
	}//end of while of "enter q to quit"
	  Systerm.out.println("Please enter a valid phone number!!");
  }//end of main
}

when i compile the code, dr java keep telling me
"File: /Users/wsun/Documents/Course summer/Comp 1010/Assignments/Work it out assgn 02/sun_wenqian_A2Q1.java [line: 23]
Error: cannot find symbol
symbol : method Replace(java.lang.String,java.lang.String)
location: class java.lang.String"

i have tried a few things, but nothing come out.
plz help

[mensahero]

Quote

digits = strInput.Replace("(","").Replace(")","").Replace("-","");

Correct me if i'm wrong.. but I don't think this is possible.. or atleast not the proper way to apply the string.replace method..

[KYA]

Yea, it takes two parameters, which are both java strings. I don't think you can call it from within itself either.

[baavgai]

mensahero, on 7 Jun, 2008 - 03:49 AM, said:

Quote

digits = strInput.Replace("(","").Replace(")","").Replace("-","");

Correct me if i'm wrong.. but I don't think this is possible.. or atleast not the proper way to apply the string.replace method..

KYA, on 7 Jun, 2008 - 04:18 AM, said:

Yea, it takes two parameters, which are both java strings. I don't think you can call it from within itself either.

Sorry folks, chaining method results is perfectly fine, as long as you get the syntax right. This works:

Quote

digits = strInput.replace("(","").replace(")","").replace("-","");

It is identical to this:

Quote

String result = strInput.replace("(","");
result = result.replace(")","");
result = result.replace("-","");
digits = result;

The String method "replace" return a new string. So, what you're doing is calling the method of the resulting value, and then calling that result's method, and so on.

Unfortunately, after all that, this would actually be more effective:

Quote

digits = strInput.replaceAll("[^0-9]", "");

The replace functions in Java use regular expressions. You can often think of them as simple find and replace, but the find part can choke if you give it a special character. In this last one, what we're saying is where the character is not (^) in the range 0-9, make it blank.

Hope this helps.

[lordms12]

Was that JAVA code, whatever here is the correct syntax I did not saw the logic.

import javax.swing.*;
public class sun_wenqian_A2Q1{
  public static void main(String args[]){
	
	//declare variables within main
	String strInput;
	String digits;
	
	
	//asking user to enter input
	strInput = JOptionPane.showInputDialog("Please enter a phone number or press q to quit the program!");

	while(strInput.equals("q")){
	  digits = strInput.replace("(","").replace(")","").replace("-","");
	  
	  int i = 0; // declare i for loops
	  int numDigits;
	  while(Character.isDigit(digits.charAt(i))){
		i++;
		numDigits = Integer.parseInt(digits);
		
		//4 kind of Phone numbers:nnnnnn,nnnnnnnnnn,nnnnnnnnnnn,if it's not "204",it's long distance
		if(numDigits == 7){
		  System.out.println("User entered: "+strInput);
		  System.out.println("Phone number parsed: ");
		  System.out.println("Valide phone number: ");
		}else if(numDigits == 10){
		  System.out.println("User entered: "+strInput);
		  System.out.println("Phone number parsed: ");
		  System.out.println("Area code: ");
		  System.out.println("Valide phone number: ");
		}else if(numDigits == 11){
		  System.out.println("User entered: "+strInput);
		  System.out.println("Phone number parsed: ");
		  System.out.println("Area code: ");
		  System.out.println("Valide phone number: ");
		}else{
		  System.out.println("User entered: "+strInput);
		  System.out.println("No Phone number parsed, invalid!");
		}//end of if else if
		
		  
		
	  }//end of while loops of "isDigits"
	  System.out.println("User entered: "+strInput);
	  System.out.println("No Phone number parsed, invalid!");
	  
	  
	  
	  //strInput = JOptionPane.showInputDialog("Please enter a phone number or press q to quit the program!");
	}//end of while of "enter q to quit"
	  System.out.println("Please enter a valid phone number!!");
  }//end of main
}

This post has been edited by lordms12: 07 June 2008 - 06:38 AM

[mensahero]

yes that is still java.. its called regular expression..


Your new code compiles fine.... doesn't encounter any error here..

[pbl]

Keep it simple do it that way:

// init phone number
int nb = 0;
// convert string read into an array of char
char[] digit = strInput.toCharArray();
// loop through the digit
for(int i = 0; i < digit.length; i++) {
	// discard the invalid values
	if(digit[i] < '0') continue;
	if(digit[i] > '9') continue;
	// add to what I already have
	nb *= 10;
	nb += (digit[i] - '0';
}

[colinwsun]

thanks veryone , it help,

to mensahero: i am so confused, I have input my code under another computer, it's still keep telling me the same thing

[mensahero]

See it does compile.. it runs.. no error..

import javax.swing.*;
public class sun_wenqian_A2Q1{
  public static void main(String args[]){
    
    //declare variables within main
    String strInput;
    String digits;
    
    
    //asking user to enter input
    strInput = JOptionPane.showInputDialog("Please enter a phone number or press q to quit the program!");

    while(strInput.equals("q")){
      digits = strInput.replace("(","").replace(")","").replace("-","");
      
      int i = 0; // declare i for loops
      int numDigits;
      while(Character.isDigit(digits.charAt(i))){
        i++;
        numDigits = Integer.parseInt(digits);
        
        //4 kind of Phone numbers:nnnnnn,nnnnnnnnnn,nnnnnnnnnnn,if it's not "204",it's long distance
        if(numDigits == 7){
          System.out.println("User entered: "+strInput);
          System.out.println("Phone number parsed: ");
          System.out.println("Valide phone number: ");
        }else if(numDigits == 10){
          System.out.println("User entered: "+strInput);
          System.out.println("Phone number parsed: ");
          System.out.println("Area code: ");
          System.out.println("Valide phone number: ");
        }else if(numDigits == 11){
          System.out.println("User entered: "+strInput);
          System.out.println("Phone number parsed: ");
          System.out.println("Area code: ");
          System.out.println("Valide phone number: ");
        }else{
          System.out.println("User entered: "+strInput);
          System.out.println("No Phone number parsed, invalid!");
        }//end of if else if
        
          
        
      }//end of while loops of "isDigits"
      System.out.println("User entered: "+strInput);
      System.out.println("No Phone number parsed, invalid!");
      
      
      
      //strInput = JOptionPane.showInputDialog("Please enter a phone number or press q to quit the program!");
    }//end of while of "enter q to quit"
      System.out.println("Please enter a valid phone number!!");
  }//end of main
}

Thats your code that I've been trying.. it does compile..

[prajayshetty]

mensahero, on 8 Jun, 2008 - 12:11 AM, said:

See it does compile.. it runs.. no error..

import javax.swing.*;
public class sun_wenqian_A2Q1{
  public static void main(String args[]){
    
    //declare variables within main
    String strInput;
    String digits;
    
    
    //asking user to enter input
    strInput = JOptionPane.showInputDialog("Please enter a phone number or press q to quit the program!");

    while(strInput.equals("q")){
      digits = strInput.replace("(","").replace(")","").replace("-","");
      
      int i = 0; // declare i for loops
      int numDigits;
      while(Character.isDigit(digits.charAt(i))){
        i++;
        numDigits = Integer.parseInt(digits);
        
        //4 kind of Phone numbers:nnnnnn,nnnnnnnnnn,nnnnnnnnnnn,if it's not "204",it's long distance
        if(numDigits == 7){
          System.out.println("User entered: "+strInput);
          System.out.println("Phone number parsed: ");
          System.out.println("Valide phone number: ");
        }else if(numDigits == 10){
          System.out.println("User entered: "+strInput);
          System.out.println("Phone number parsed: ");
          System.out.println("Area code: ");
          System.out.println("Valide phone number: ");
        }else if(numDigits == 11){
          System.out.println("User entered: "+strInput);
          System.out.println("Phone number parsed: ");
          System.out.println("Area code: ");
          System.out.println("Valide phone number: ");
        }else{
          System.out.println("User entered: "+strInput);
          System.out.println("No Phone number parsed, invalid!");
        }//end of if else if
        
          
        
      }//end of while loops of "isDigits"
      System.out.println("User entered: "+strInput);
      System.out.println("No Phone number parsed, invalid!");
      
      
      
      //strInput = JOptionPane.showInputDialog("Please enter a phone number or press q to quit the program!");
    }//end of while of "enter q to quit"
      System.out.println("Please enter a valid phone number!!");
  }//end of main
}

Thats your code that I've been trying.. it does compile..

ya it compiles even i checked good work

[colinwsun]

thanks man! it's so weird. gonna try compile my code on library machine tonight.