[daddymac1213]

// Adams, Christopher
// Lab4 exercise2
// This program creates two triangles based on user input. The first triangle is displayed and the second triangle is the inverse of the first triangle.

#include "stdafx.h"
#include <iostream>
using namespace std;


void printTriangle (int);
void printTriangle2 (int);
int base = 0;

int main(void)
{
	cout << "Enter the size of your base: ";
	
	cin >> base;
	
	cout << endl;
	printTriangle (base);
	printTriangle2 (base);
}


void printTriangle (int prntTri)
{
	for(int i = 0; i < prntTri; i++)
{
	 for(int j = 0; j <= i; j++)
 {
	  cout << "*";
   }
   cout<<endl;
   
}
}

void printTriangle2 (int prntTri)
{
	for(int i = 0; i < prntTri; i++)
{
	 for(int j = prntTri; j > i; j--)
	 {
	  cout << "*";
   }
   cout<<endl;
   
}
}

I am supposed to write a program that uses functions to display a triangle based on the user's input and the inverse of that same triangle. I got this program to do just that, but the second function is supposed to be an overloaded function of the first function. I'm not exactly sure how overloaded functions work, can anybody help?

[KYA]

Overloaded functions have the same name, but take different paramters (either in type or number or both).

Example:

void printTriangle(int);
void printTriangle(int, int);
void printTriangle(double); //etc... program will select function based on context

However, both of your functions take the same number and type of parameters so it will need to be changed.

[daddymac1213]

I'm stiil not sure if I understand what you're getting at. I can't change the type for the second triangle to double instead of int. like so?

#include "stdafx.h"
#include <iostream>
using namespace std;


void printTriangle (int);
void printTriangle (double);
int base = 0;

int main(void)
{
	cout << "Enter the size of your base: ";
	
	cin >> base;
	
	cout << endl;
	printTriangle (base);
	printTriangle (base);
}


void printTriangle (int prntTri)
{
	for(int i = 0; i < prntTri; i++)
{
	 for(int j = 0; j <= i; j++)
 {
	  cout << "*";
   }
   cout<<endl;
   
}
}

void printTriangle (double prntTri)
{
	for (double i = 0; i < prntTri; i++)
{
	 for(double j = prntTri; j > i; j--)
	 {
	  cout << "+";
   }
   cout<<endl;
   
}
}

This post has been edited by daddymac1213: 23 November 2008 - 06:32 PM

[KYA]

Well you have to change other things also. Your input variable is still an integer and the second overloaded function would never be called. Especially since you are only printing a shape based on an integer, I don't see why operator overloading is necessary at all. Even as an academic constraint, it makes no sense for this assignment.

[daddymac1213]

I know but that was part of the instructions included in the assignment. I found another way to display the same output, just not by overloading the first function. Thanks for your help.

[Plus]

hmm,
you can merge the two functions into one to be ...


void PrintTriangle (int Length,bool Direction){
if(Direction){
for(...){ "print triangle to UP" }
else
for(...){ "print triangle to DOWN" }
}