[ic3e]

I know there is a simple solution, so here is my program.

 #include<iostream>
 #include<string>

using namespace std;

int main()
{
double min;
double BasicRate;
double CStates;
double FStates;
double cost = 0;

string inp = "";
string temp = "";
BasicRate = 0.02;
CStates = 1.25 * BasicRate;
FStates = 1.75 * BasicRate;
int callCount;



for(int i = 0; i < 10; i++)
{
 temp = inp[0];
 if(temp == "q" || temp == "Q") break;
 cout << "------------------------------------------\n";
 cout << "Q & A Telephone service.\n";
 cout << "------------------------------------------\n";
 cout << " plaease enter your destenation number ex."
"111-111-1111\n";
 cin >> inp;
 temp = inp[0] + inp[1] + inp[2];

 
 {
 if(temp == "405") cost = BasicRate * min * (rand() % 180);
 if( temp == "550" ||  temp == "520") cost= CStates * min * (rand() %
180);
 if(temp == "620" || temp  == "650") cost = FStates * min * (rand() %
180);
 cout << cost"\n";

 }

cout << " over limit\n ";
}

Its not complete, Im just dividing and conquering portions at a time. when I run this program, it prompts the user to enter A phone number, after the user enters the phone number, it loops right back around to the beginning, which is ok for now. Im just trying to figure out how to make the program go throught the loop only 10 ten times then to tell the user his time is up. should I use a for loop or a while loop?

[programble]

Your code looks just fine, are you getting errors?

[ic3e]

programble, on 28 Feb, 2009 - 11:56 AM, said:

Your code looks just fine, are you getting errors?

Yeah, it works so far, when I run this program, it prompts the user to enter A phone number, after the user enters the phone number, it loops right back around to the beginning, which is ok for now. Im just trying to figure out how to make the program go throught the loop only 10 ten times then to tell the user his time is up. should I use a for loop or a while loop?

[krisku]

Can use do-while loop. Syntax:

do {
something
something2
} while(expression)

For counting, can use variable with initial value 0. ;-)

This post has been edited by krisku: 28 February 2009 - 01:29 PM

[ic3e]

krisku, on 28 Feb, 2009 - 12:27 PM, said:

Can use do-while loop. Syntax:

do {
something
something2
} while(expression)

For counting, can use variable with initial value 0. ;-)

I incorporated this method

#include<iostream>
 #include<string>

using namespace std;

int main()
{
double min;
double BasicRate;
double CStates;
double FStates;
double cost = 0;

string inp = "";
string temp = "";
BasicRate = 0.02;
CStates = 1.25 * BasicRate;
FStates = 1.75 * BasicRate;
int callCount;

do
{

for(int i = 0; i < 10; i++)
{
 temp = inp[0];
 if(temp == "q" || temp == "Q") break;
 cout << "------------------------------------------\n";
 cout << "Q & A Telephone service.\n";
 cout << "------------------------------------------\n";
 cout << " plaease enter your destenation number ex."
"111-111-1111\n";
 cin >> inp;
 temp = inp[0] + inp[1] + inp[2];

 
 {
 if(temp == "405") cost = BasicRate * min * (rand() % 180);
 if( temp == "550" ||  temp == "520") cost= CStates * min * (rand() %
180);
 if(temp == "620" || temp  == "650") cost = FStates * min * (rand() %
180);
 cout << cost"\n";

 }
 } while( cin < 10);
cout << " over limit\n ";
}

I ran it, and got multiple errors, any Ideas?

[programble]

Use a for loop.
for (int c = 0; c < 10; c++)